-4.9t^2-3t+550=0

Solution for -4.9t^2-3t+550=0 equation:

-4.9t^2-3t+550=0

a = -4.9; b = -3; c = +550;
Δ = b2-4ac
Δ = -32-4·(-4.9)·550
Δ = 10789
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{10789}}{2*-4.9}=\frac{3-\sqrt{10789}}{-9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{10789}}{2*-4.9}=\frac{3+\sqrt{10789}}{-9.8}
$